
Tim T. answered 03/24/19
Math: K-12th grade to Advanced Calc, Ring Theory, Cryptography
Yes, M is diagonalizable.
Proof: Let the matrix M be a matrix consisting of polynomials of characteristic 2 where I is the identity matrix such that,
M2-3M+2I = X2-3X+2.
The polynomial is factor-able in M such that X2-3X+2 = (X-1)(X-2).
A square matrix is diagonalizable if (and only if) its minimal polynomial factors completely into distinct linear factors over the base field F. The factors X-1 and X-2 are distinct over any field (even a field of characteristic 2). Thus, M is diagonalizable.