Isabella M.

asked • 03/20/19

Series n/((n+1)(n+2)(n+3)) from 1 to infinity is equal to 1/4. Why?

2 Answers By Expert Tutors

By:

Isabella M.

I did that, and I got -1/2(n+1) + 2/(n+2) - 3/2(n+3), but I don't see the form of a telescoping series.
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03/20/19

Steven G.

tutor
(1/2)(-1/(n+1) + 4/(n+2) -3/(n+2)) = (1/2)[(-1/(n+1)+1/(n+2))+3(1/(n+2) -1/(n+3))]. Grouping things this way does give a telescoping series!!!
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03/20/19

Isabella M.

Thank you so much!
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03/21/19

Steven G.

tutor
Doctoral level math tutor using excel?? No comment at all
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03/20/19

Jason P.

Steven, thanks for the comment. Please be sure you treat other users on AAE respectfully, and that when you reply, you are providing help for a question.
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03/21/19

John T.

tutor
Steven, my graduate training is in physiology, cell biology, and public health. Sometimes students can see things from the non-subject instructor perspective more clearly, just like I presume you might when, say, examining the mechanisms of alkane bromination via radical intermediates. The reason for Excel is because the series was not approaching 1/4 very quickly. It was nothing more than a convenience. Your explanation that the series is telescoping after written as a partial fraction is more concise. Thank you and have a great day.
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03/21/19

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