Write it as a partial fraction. ?/(n+1) + ??/(n+2) + ???/(n+3). Then you see that it is a telescoping series.
Isabella M.
asked 03/20/19Series n/((n+1)(n+2)(n+3)) from 1 to infinity is equal to 1/4. Why?
2 Answers By Expert Tutors
John T. answered 03/20/19
Doctoral-level tutoring for STEM, Biostatistics, SAT/ACT, and GRE
First, the series converges as demonstrated by either the direct comparison test or the limit comparison test. You can compare this series to 1/n2, a convergent p-series. With these tests, if the limits of the two expressions do the same thing, then the two series both converge or both diverge. Also, you should show that as n increases the series of interest produces smaller elements than does 1/n2.
Next, if you program Excel to find the first 400 terms and the sum of the first 400 terms, you'll see the sum, rounded to three decimal places, is 0.248. Moving to the 0.249 is going to take many more terms. You can approximate by finding the integral of the sequence explicit form with respect to n from 0 to 400 and have a fair estimate of 0.259.

Steven G.
03/20/19
Jason P.
Steven, thanks for the comment. Please be sure you treat other users on AAE respectfully, and that when you reply, you are providing help for a question.03/21/19

John T.
03/21/19
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Isabella M.
I did that, and I got -1/2(n+1) + 2/(n+2) - 3/2(n+3), but I don't see the form of a telescoping series.03/20/19