8 Answered Questions for the topic Convergence

12/01/21

Why isn't this series convergent?
Hello! I'm trying to solve the following series through the alternating series test:cos(n pi) / n^(1/n), with the series starting at 1 and going to infinity. I started by finding the first... more
Follows • 1
Expert Answers •1
Convergence Calculus

11/18/20

Please help check my answer? Which of the following series converges conditionally?
Which of the following series converges conditionally? Diverges Converges Diverges Converges Conditionally? I chose this
Follows • 1
Expert Answers •1
Convergence Integrals True Or False

10/05/20

True or False? Convergence
True/ False: If f is continuous on [0, ∞) and the (integral of 1 to ∞) from f(x)dx is convergent, then the (integral of 0 to ∞) from f(x)dx is convergent
Follows • 1
Expert Answers •1
Convergence Math Calculus Series

04/08/20

Determine if the series is absolutely convergent, conditionally convergent, or divergent.sum of n=1 to infinity of (n+2)/sqrt (n^5-n+1)
NEED ASAP!! please provide step by step solution and answers. Thank you.
Follows • 1
Expert Answers •1
Convergence Calculus Sequences Series

03/08/20

Determine whether the sequence is convergent or divergent. If it is convergent, find the limit: an=sin^3((-1)^n(n^-2))
Please help! Need answer ASAP! Please answer with step by step explanation. Thank you.
Follows • 1
Expert Answers •1

12/12/19

Direct Comparison Test to determine divergence or convergence
the series from 1 to infinity is: 5/ (n^(1/3)-2)The question is to determine convergence or divergence using direct comparison test. I wasn't sure how to do this because there's no value of bn that... more
Follows • 2
Expert Answers •2
Convergence Calculus Proofs

05/05/19

mathematical proof

Claim: If a(sub)n converges to A then (c+a(sub)n) converges to c+A
Follows • 1
Expert Answers •1
Convergence Calculus Series

03/20/19

Series n/((n+1)(n+2)(n+3)) from 1 to infinity is equal to 1/4. Why?
Follows • 1
Expert Answers •2

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.