Patricia D. answered • 03/16/19

Able to explain concepts so students understand

The zeros of P(x)=x^2+4 are

To find the Zeros, set P(x) = 0

x^{2 }+4 = 0

x^{2} = -4 so

x = 2i, -2i

x1= …0…. + …2……. i with negative imaginary part,

it's multiplicity is ……1…… ; and

x1= 0……. + …-2……. i with positive imaginary part,

it's multiplicity is …1……… .