The sum of squares of two positive consecutive even numbers is 244. Find the numbers. List the least one first and separate the answers with a comma but no spaces.

Answer 1

n² + (n + 2)² = 244

n² + n² + 4n + 4 = 244

2n² + 4n - 240 = 0

n² + 2n - 120 = 0

n² + 12n - 10n - 120 = 0

n(n + 12) - 10(n + 12) = 0

(n - 10)(n + 12) = 0

n - 10 = 0

n = 10

10,12

n + 12 = 0

n = -12

We're looking for pisitive numbers, so we disregard.