Raymond B. answered 05/03/21
Math, microeconomics or criminal justice
1/10 + 1/15 + 1/20 + 1/T where T = hours working all together
multiply by 60T
6T + 4T + 3T = 60
13T = 60
T = 60/13 = about 4.615 hours =4.6 hours rounded off to one decimal
Let's say they all averaged 15 hours, which they do, or assume they all could do it alone in 15 hours. 3 people would then do it in exactly 15/3 = 5 hours
the closer they are to equality, the closer they will be to 5 hours. 4.6 is close
10 and 20 are close to 15.
the 1st does 1/10 of the job in 1 hour, the 2nd does 1/15 of the job in 1 hour
the 3rd does 1/20 of the job in one hour.
Add them all up and that's the fraction they all do together in 1 hour
put them over a common denominator: 60T
1/10 + 1/15 + 1/20 = 1/T
6T/60T + 4T/60T + 3T/60T = 60/60T
add them up
(6T+4T+3T)/60T = 60/60T
13T/60T = 60/60T
if the denominators are the same on left and right sides, then the numerators are equal
13T =60. divide by 13
T =60/13 = about 4.5 hours working together.