
Eri S. answered 08/29/19
Friendly Math Specialist :^)
Hi El K, this is a fun problem! Let's try to keep things simple by looking at the categories separately at first.
In groups of 3: for 10 players to get exactly 10 turns each, there will have to be 100 turns in total. Each round, 3 players get 1 turn (3 turns altogether). So, let's divide the 100 turns by 3 to see how many rounds of the game it will take for everyone to get 10 turns. 100 divided by 3 equals 33 with a remainder of 1. That means 1 player misses out on a 10th turn if only 33 rounds are played. It will take a minimum of 34 rounds for all 10 players to get all 10 turns. 2 lucky players get 11 turns.
Here's the long way: let's name each player a letter from A to J: A B C D E F G H I J.
Now let's play the game:
I copied and pasted the 10 letters 10 times, and then pressed return after every 3 letters, then numbered the rows. This proves that you need 34 rounds.
- ABC
- DEF
- GHI
- JAB
- CDE
- FGH
- IJA
- BCD
- EFG
- HIJ
- ABC
- DEF
- GHI
- JAB
- CDE
- FGH
- IJA
- BCD
- EFG
- HIJ
- ABC
- DEF
- GHI
- JAB
- CDE
- FGH
- IJA
- BCD
- EFG
- HIJ
- ABC
- DEF
- GHI
- JAB
The same methods can be used for the other categories.
For groups of 5: 20 rounds are needed because 100 divided by 5 equals 20 with no remainder.
- ABCDE
- FGHIJ
- ABCDE
- FGHIJ
- ABCDE
- FGHIJ
- ABCDE
- FGHIJ
- ABCDE
- FGHIJ
- ABCDE
- FGHIJ
- ABCDE
- FGHIJ
- ABCDE
- FGHIJ
- ABCDE
- FGHIJ
- ABCDE
- FGHIJ
For groups of 7: 15 rounds are needed because 100 divided by 7 equals 14 with a remainder of 2.
- ABCDEFG
- HIJABCD
- EFGHIJA
- BCDEFGH
- IJABCDE
- FGHIJAB
- CDEFGHI
- JABCDEF
- GHIJABC
- DEFGHIJ
- ABCDEFG
- HIJABCD
- EFGHIJA
- BCDEFGH
- IJABCDE
Now, we just need to add up the rounds for the 3 categories. 34 + 20 + 15 = 69 rounds total.
I hope you find this explanation helpful. :^)