
Patrick B. answered 02/23/19
Math and computer tutor/teacher
8a + 5c = 180.50
12a + 6c = 261
elimination: 3 * eq1 + -2 * eq 2
24a + 15c = 541.5
-24a + -12c = -522
3c = 19.5
c = 6.50
12a + 6*6.50 = 261
12a + 39 = 261
12a = 222
a = 18.50
Teairra N.
asked 02/23/19The circus is coming. Cindy is selling tickets. she sold 8 adults tickets and 5 children's tickets for a total of $180.50 in sales. The second day she received $261.00 for 12 adult tickets and 6 children tickets. What is the price of a child's ticket? What is the price of an adult ticket?
Write two algebraic equations that model this circus ticket scenario
Patrick B. answered 02/23/19
Math and computer tutor/teacher
8a + 5c = 180.50
12a + 6c = 261
elimination: 3 * eq1 + -2 * eq 2
24a + 15c = 541.5
-24a + -12c = -522
3c = 19.5
c = 6.50
12a + 6*6.50 = 261
12a + 39 = 261
12a = 222
a = 18.50
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Renee W.
Where did you get the 3 and the 2 that you used to multiply by eq1 and eq2?04/22/19