Doug C. answered • 02/18/19

Math Tutor with Reputation to make difficult concepts understandable

Alyna C.

asked • 02/18/19Log_{5}(x^{2}) = 1 + Log_{5}(6)

- Uses rule a=log
_{b}(b^{a}) to get log_{5}(x^{2}) = log_{5}(30) - x
^{2}= 30 - x = square of 30

There is nothing online about “1 + logarithms” and when there is they expotentate. Why is this rule used? Everything is easy except for when it is explained as “log_{5}(5^{1+log}_{5}^{(6)})” which somehow equals 30

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Doug C. answered • 02/18/19

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Math Tutor with Reputation to make difficult concepts understandable

note that log5(5) = 1 so

log5(x^2) = log5(5) + log5(6)

5^log5(x^2) = 5^log5(5) * 5^log5(6)

x^2 = 30

x = sqrt(30)

Jeremy E.

tutor

i would be happy to tutor you :)
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02/18/19

Alyna C.

Oh thanks so much! I didn’t connect the dots there and my boyfriend wanted help on this stuff which got me into it! It was really nice to learn.
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02/18/19

Jeremy E.

tutor

no problem. rates vary. I assume your boyfriend/you is a student? If this is the case, and since i'm fairly new to wyzant, i could offer a rate of $25/hr.
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02/19/19

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Alyna C.

Wow thanks a lot I didn’t expect a video! You made everything really clear to understand! Thank you so much Doug02/18/19