the shape is ring-like, with one end wider then the other, and the edges sharp.
r(inside) = x^2+2
r(outside) = sqrt(x)+2
int(Pi(*ro^2-ri^2))dx x=0..1
Pi*int((sqrt(x)+2)^2-(x^2+2)^2)dx
Pi(int(x+4sqrt(x)+4-x^4-4x^2-4)dx
Pi*int(-x^4-4x^2+x+sqrt(x))dx
i leave the rest to you
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