the shape will be a tall bowl figure with a flat bottom.
This is the 2D shape in question being rotated
the discs will be horizontal so the integration variable will be y
INT(Pi*r^2)dy - y=1..8
INT(Pi*(sqrt(y)^2)dy
Pi*INT(y)
Pi*y^2/2 y=1..8
Pi*32-Pi/2 = 63Pi/2