Prove: triangle ABC is congruent to triangle DCB of the given is "angle 1 is congruent to angle 2, line segment AB is parallel to line segment DC

Question

A___________________________B

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C|___________________________|D

Imagine that a line cutting the square in half diagonally in this (/) direction. At the end near "C" is angle 1 and at the other end near "B" is angle 2

Answer 1

This forum doesn't work well when pictures are involved. I can't really see what's going on but I'm guessing, because you have parallel line segments, you can show that two angles are congruent using the alternate interior angle theorem. Then use Angle-Side-Angle to prove congruence. But, again, it's hard to know because I can't see a picture of what's going on.