L = 2W + 4
2(L + W) = 68
L + W = 34
Now substitute
2W + 4 + W = 34
3W = 30
You solve it from here!
Amiya B.
asked 02/05/19The length of a rectangle is 4ft more than twice the width. The perimeter is 68ft. Find Dimensions
L = 2W + 4
2(L + W) = 68
L + W = 34
Now substitute
2W + 4 + W = 34
3W = 30
You solve it from here!
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