Since 6i is a zero of f(x), so is -6i..
f(x) = (x-4)2(x-6i)(x-(-6i))
= (x-4)2(x-6i)(x+6i)
= (x2 - 8x + 16)(x2 + 36)
= x4 + 36x2 - 8x3 - 288x + 16x2 + 576
= x4 - 8x3 + 52x2 - 288x + 576
Raul P.
asked 02/02/19degree of 4 and zeros: 4, multiplicity 2; 6i
Since 6i is a zero of f(x), so is -6i..
f(x) = (x-4)2(x-6i)(x-(-6i))
= (x-4)2(x-6i)(x+6i)
= (x2 - 8x + 16)(x2 + 36)
= x4 + 36x2 - 8x3 - 288x + 16x2 + 576
= x4 - 8x3 + 52x2 - 288x + 576
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