
Patrick B. answered 01/20/19
Math and computer tutor/teacher
f(-3) = (-3)^3 - 5 = -27-5 = -32
f(2) = 2^3 - 5 = 8 - 5 = 3
(-3,-32) vs (2,3)
slope of the secant line is (-32 - 3)/(-3-2) = -35/-5 = 7
B = y - mx = 3 - 7*2 = 3-14 = -11
y = 7x - 11
Yo F.
asked 01/19/19Given f(x) =x^3-5 , find the equation of the secant line passing through , (−3,f (−3)) and ,( 2f (2)) . Write your answer in the form y=mx+b
Patrick B. answered 01/20/19
Math and computer tutor/teacher
f(-3) = (-3)^3 - 5 = -27-5 = -32
f(2) = 2^3 - 5 = 8 - 5 = 3
(-3,-32) vs (2,3)
slope of the secant line is (-32 - 3)/(-3-2) = -35/-5 = 7
B = y - mx = 3 - 7*2 = 3-14 = -11
y = 7x - 11
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