Mark M. answered 01/20/19
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Δx = (9-1)/n = 8/n
Divide the interval [1,9] into n equal subintervals each of width Δx.
Right endpoint of first interval = 1 + Δx
Right endpoint of 2nd interval = 1 + 2Δx
Right endpoint of 3rd interval = 1 + 3Δx......
Right endpoint of last interval = 1 + nΔx = 9
Rn = Σ(i = 1 to n) [f(1 + iΔx)Δx]
∫(from 1 to 9)f(x)dx = limn→∞Rn =
limn→∞[∑(i = 1 to n){(1 + 8i/n)-3(8/n)}]