calculate the equation

Question

0.033x+x²-1.5876×10^-10=0

Answer 1

0.033x + x² - 1.5876*10^-10 = 0

 

re-writing in standard form:

 

x² + 0.033x - 1.5876*10^-10 = 0

 

This is a quadratic equation of the form y = ax2 + bx + c, so use the quadratic formula:

 

x = (-b/2a) ± (1/2a)[b² - 4ac]^1/2

 

In this case, a = 1, b = 0.033, and c = -1.5876*10^-10

 

x = (-0.033/2) ± (1/2)*[(0.033)² - (4)(1)(-1.5876*10^-10)]^1/2

 

The 10^-10 term doesn't add much to the (0.033)², so the answer is basically:

 

x = -0.0165 ± 0.0165000048109, which is pretty close to -0.033 and 0. Strange problem.