Inactive Tutor answered 01/14/19
First, we must solve for f(x+2). When x is x+2, then f(x+2)=(x+2)2--->x2+4x+4. Now, when x in the function g(x)=x-3 is x2+4x+4 we get g(x2+4x+4)=(x2+4x+4)-3--->x2+4x+1. Therefore, the answer is x2+4x+1.
Bob G.
asked 01/13/19Given f(x)=x^2 and g(x)=x-3, express g(f(x+2)) as a polynomial in simplest form.
Inactive Tutor answered 01/14/19
First, we must solve for f(x+2). When x is x+2, then f(x+2)=(x+2)2--->x2+4x+4. Now, when x in the function g(x)=x-3 is x2+4x+4 we get g(x2+4x+4)=(x2+4x+4)-3--->x2+4x+1. Therefore, the answer is x2+4x+1.
f(x) = x2
g(x) = x - 3
To find f(x+2), just replace the x with x+2:
f(x+2) = (x+2)2 = x2 + 4x + 4
To find g(f(x+2)), just replace the x in g(x) with f(x+2):
g(f(x+2)) = f(x+2) - 3 = x2 + 4x + 4 - 3 = ______?
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