3F + 2S = 8
2F - S =3
where F = 1st number and S = 2nd number
S=2F-3 (from the second equation)
Substitute
3F + 2(2F-3) = 8
3F + 2F - 6 = 8
7F = 14
F=2
S=1 by substitution of F=2 into the equation for S
Check your answer!
Chaya A.
asked 01/07/19The sum of three times a first number and twice a second number is 8. If the second number is subtracted from twice the first number, the result is 3. Find the numbers.
3F + 2S = 8
2F - S =3
where F = 1st number and S = 2nd number
S=2F-3 (from the second equation)
Substitute
3F + 2(2F-3) = 8
3F + 2F - 6 = 8
7F = 14
F=2
S=1 by substitution of F=2 into the equation for S
Check your answer!
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