Since machine A is twice as fast as machine B, B makes 1/3 of the total copies made and A make 2/3.
In one hour the two machines together would make 4140 copies, i.e. A makes 2760 copies per hour and B makes 1380 copies per hour.
Machine C also makes 2760 copies per hr but works 1/6 of an hour less than the other 2, i.e.
(2760+1380)T + [T-(1/6)]2760 = 2080 where T is the time worked by the first 2 machine together.
6900T = 2070+460 = 2530 and
T = .366666666 hrs or 22 minutes, i.e. 8 minutes less by adding the 3rd machine.