Dave has some gum. Bill has two times as much gum as Dave. Matt has three more packs as Dave. Joe has 3 times as many packs as Matt. Altogether, the boys have 54 packs of gum.

Answer 1

b = 2d

m = 3+d

j = 3m

d +b+m +j = 54

d + 2d + 3+d + 3(3+d) = 54

7d = 54 -9 -3= 42

d = 42/7 = 6 for Dave

b = 12 for Bill

m = 9 for Matt

j = 27 for Joe

6+12+9+27 = 54