Set up and solve

Question

Find two consecutive odd integers such that the square of the first, added to 3 times the second, is 24.

Answer 1

The odd numbers are 2k-1 and 2k+1

(4k² - 4k + 1) + 6k +3 = 24

4k²+2k+4=24

You can solve this quadratic, but one of the roots is extraneous.