What is an equation of the line that is perpendicular to y - 4 = 2 (x-6) and passes the point (-3, -5)?

Answer 1

y - 4 = 2x - 12

y = 2x - 8

Perpendicular line has slope (-1/2)

B = y - mx

= (-5) - (-1/2)(-3)

= (-5) - 3/2

= (-10/2) - 3/2

= -13/2

y (-1/2)x - 13/2