a ball is thrown off a building from 200 feet above the ground its starting velocity is -10 feet per second about how long does it take the ball to hit the ground

Question

the equation h=-16t^2-10t+200 can be used to model the height of the ball after t seconds

Answer 1

h(t) = 0 = -16t^2 -10t + 200

divide by -2

8t^2 +5t -100 = 0

t =about 3.236817716 seconds to hit the ground

= about 3 1/4 seconds

use the quadatic formula or graph the parabola and find the positive x intercept with time t on the x axis and h on the y axis

t = -5/16 + (1/16)sqr(25 +3200)