Inactive Tutor answered 10/25/14
Tutor
New to Wyzant
Hi Lena,
Gravity is gravity is gravity (as long as you are outside the black hole).
Part a)
In a circular orbit the gravitational force causes the centripetal acceleration; additionally v =2πr/T. One can then write
GMm/r2 = mv2/r and substituting in for v find that T2 = (2π)2r3/(GM) (one of Kepler's laws)
This will certainly work for our observer at infinity.
(sorry for the interrupt, I need to take a break here)
Inactive Tutor
10/25/14