how do you determine the largest rectangle possible to allow for the maximum space to plant a vegetable garden if the class have 64 feet of fencing?

Answer 1

P = 2L + 2w

64 = 2L + 2w

32 = L + w

L = 32 - w

Area = L * w

= (32 - w)w

Max area occurs at the average of the zeros, which are 0 and 32.

The max occurs at w=(0+32)/2 = 32/2 = 16

Area = 16*16 = 256