Graph the expression!
Yes, you have the critical points correctly, but 9/4 is a minimum and 0 is a point of inflection with a horizontal tangent, where the 2nd derivative is 0.
Soju H.
asked 11/13/18Hi, I got a Calculus problem I just want to verify that I got right
I got the critical points at x=0 and 9/4, possible inflection points at x=0 and x=3/2, and to find the intervals over which f(x) is increasing, decreasing, concave up or down, I just plug the inflection points on an x axis and find out whether it's +(con up) or -(con down) on each side of the inflect. pts, and to find the increasing, decreasing, I just do the same thing with critical pts, yes?
I put decreasing as (- infinity, 9/4) but apparently there was supposed to be a bracket around 9/4 (including), I'm not sure why?
And I have concave up in (- infity, 0) but concaving down in (0, infinity) is incorrect.. Can someone explain why?
Thank you
Graph the expression!
Yes, you have the critical points correctly, but 9/4 is a minimum and 0 is a point of inflection with a horizontal tangent, where the 2nd derivative is 0.
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