Lauren H. answered 11/12/18
Tutor
4.8
(24)
Experienced High School Chemistry Teacher
p(.01) + n(.05) = .39
p = 8n
Substitute:
8n(.01) + n(.05) = .39
.08n + .05n = .39
.13n = .39
n = 3
p = 24
Hollyann P.
asked 11/12/18
Lauren H. answered 11/12/18
Experienced High School Chemistry Teacher
p(.01) + n(.05) = .39
p = 8n
Substitute:
8n(.01) + n(.05) = .39
.08n + .05n = .39
.13n = .39
n = 3
p = 24
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.