HELP i need help pls

Question

Derek walks along a road which can be modeled by the equation y=2x, where (0,0) represents his starting point. When he reaches the point (7,14), he turns right, so that he is traveling perpendicular to the original road, until he stops at a point which is due east of his starting point (in other words, on the x-axis).

What is the point where Derek stops?

Answer 1

he went from (0,0) to (7.14) then 90 degree turn straight to (35,0)

he went along the line y=2x, then on a line y =-x/2 + 35/2

0 = -x/2 + 35/2

x/2 = 35/2

x = 35 = x intercept = the point (35,0)

to find the perpendicular line use the negative inverse slope, take 2 change its sign and flip it upside down to get slope = -1/2. then plug (7,14) into y =-x/2 +b to find "b" which then = 35/2

giving the line: y = -x/2 +35/2 Then find the x intercept by setting y = 0 and solve for x = 35, = the point (35,0) where he ends up, due east of where he started