if an object is dropped from 2890 feet such that h=2890-16t^2 how much time would it take for it to be 770 feet from the ground

Question

if an object is dropped from 2890 feet such that h=2890-16t^2 how much time would it take for it to be 770 feet from the ground

Answer 1

h = 2890 - 16t^2

h is height. The height at the time of the equation will be 770.

770 = 2890 - 16t^2

Now you want to solve for t (which stands for time)

Subtract 2890 from both sides. 770-2890 = -2120

-2120 = -16t^2

Now divide both sides by - 16. -2120/-16 = 132.5

132.5 = t^2.

Finally, take the square root of both sides. The square root of 132.5 is 11.5.

11.5 seconds is your answer.