n2 = 50 + 2(n - 5)2
n2 = 50 + 2(n2 - 10n + 25) = 50 + 2n2 - 20n + 50
n2 - 20n + 100 = (n -10)2 => n = 10
Erica F.
asked 10/29/18How do I get the equation to solve this problem. For the square of a number is fifty more than twice the square of the number that's five less
n2 = 50 + 2(n - 5)2
n2 = 50 + 2(n2 - 10n + 25) = 50 + 2n2 - 20n + 50
n2 - 20n + 100 = (n -10)2 => n = 10
Lauren H. answered 10/30/18
Experienced High School Chemistry Teacher
For the square of a number is fifty more than twice the square of the number that's five less
n^2 = 50 + 2(n-5)^2
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