What is the center and radius of the circle with equation (y-6)^2=25-(x-3)^2.

Question

What is the center and radius of the circle with equation (y-6)^2=25-(x-3)^2.

Answer 1

The equation for a circle is ( x − h )² + ( y − k )²= r², where (h,k) is the center and r² is the center. So first, let's re-write the given equation with the variables on one side:

The center is (3,6) the radius = √25 = 5.