Solving a percent mixture problem and

Question

Racheal invested her savings in two investment funds. The amount she invested in Fund A was $3000 less than the amount she invested in Fund B. Fund A returned a 8%profit and Fund B returned a 3% profit . How much did she invest in Fund A, if the total profit from the two funds together was 1300?

Answer 1

.08(x-3000) + .03x = 1300

.11x = 1300 +240 = 1540

x = 1540/.11= $14000 invested at 3%

x -3000 = $11,000 invested in 8%