
Mark M. answered 10/24/18
Mathematics Teacher - NCLB Highly Qualified
0 = 5(x - 4)2 + 180
Can you solve for x and answer?
Des A.
asked 10/24/18An object is launched from a platform. It’s height (in meters), x seconds after the launch, is modeled
h(x)=-5(x-4)2+180
how many seconds after being launched will the object hit the ground?
Mark M. answered 10/24/18
Mathematics Teacher - NCLB Highly Qualified
0 = 5(x - 4)2 + 180
Can you solve for x and answer?
Andy C. answered 10/24/18
Math/Physics Tutor
0 = -5(x-4)^2 + 180
-180 = -5(x-4)^2
36 = (x-4)^2
+-6 = x-4
x = 4+6=10 or x = 4-6=-2
x is time and cannot be negative
so 10 seconds
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