6(1-3i)-(11-17i)

Question

I need help with this question from a worksheet called Equality, Addition and Subtraction of Complex numbers

Answer 1

Hello, DeeDee

 

Just do the distributive property the regular way.  Just remember that i*i = -1.  So in this case, this is what you have

 

6(1-3i)- (11-17i)=

6-18i-11+17i                        Remember -(11-17i) think of this as -1(11-17i)

-i-5                                      Combining like terms

-5-i                                      Rewriting it in the Standard Form

 

So, remember if you add or subtract complex numbers just think treat them just like a variable. 

 

I hope this helps out.  Please rate the answer.

 

D. Y. Taylor

Answer 2

6(1 - 3i) - (11 - 17i)

 

6 - 18i - 11 + 17i

 

-5 -i