solving rational expressions

solving rational expressions

Tutors, please sign in to answer this question.

Cross multiply to get:

a(a+1) = 3(a+5), expand

a^{2} + a = 3a + 15, set equal to 0

a^{2} - 2a - 15 = 0, factor

(a - 5) (a + 3) = 0, set each term to 0

(a - 5) = 0 and (a + 3) = 0, solving for each

a = 5 or a = -3

John, given a/(a+5)=3/(a+1) get rid of the fractions by multiplying both sides by (a+5)(a+1)

which gives a^{2} - 2a - 15=0 this factors into (a-5)(a+3) so the roots are a=5,-3

Regards

Jim

Tiffany G.

GRE, GMAT, SAT, NYS Exams, and Math

New York, NY

5.0
(1144 ratings)

Marc P.

Ivy League Grad to Help with Standardized Tests and Academic Work

New York, NY

4.9
(253 ratings)

Tonia M.

Double-Ivy-League-Educated, PhD tutor passionate about teaching!

New York, NY

5.0
(32 ratings)