Let x = the side of the square base and y = height
Let V = volume = x2y
The surface area = 2x2 + 4xy = 121.5
Solve the surface area equation for y = (121.5 - 2x2)/4x and substitute this into the volume equation
V = x2(121.5 - 2x2)/4x = x(121.5 - 2x2)/4
the derivative of V with respect to x = (x/4)(-2x) + (1/4)(121.5 - 2x2) = 0 at the maximum
(1/4)(-4x2 + 121.5 - 2x2) = 0'
6x2 = 121.5
x2 = 20.25
x = 4.5
y = (121.5 - 40.5)/(4 * 4.5) =81/18 = 4.5
The the rectangular solid with maximum volume for given surface area is, in fact, a cube with side 4.5.
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Paul M.
tutor
Thanks.
I hope it was helpful.
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10/05/18
Mike J.
10/05/18