find the dimensions and perimeter of the tabletop.

Question

a Rectangular tabletop that has the length that is twice it’s width. The tabletop measures 76 inches on its diagonal. 

Answer 1

Let w = the width

Let 2w = the length

a² + b² = c²

(2w)² + w² = 76²

4w² + w² = 5776

5w² = 5776

w² = 1155.2 

w ≅ 33.988 

2w ≅ 67.976 inches