help me with this

Question

If the solutions to a quadratic equation are 2 and - 3, then you can find the original equation by multiplying:

A.
(x + 2)(x - 3) = 0

B.
(x - 2)(x + 3) = 0

C.
(x + 2)(x +3) = 0

D.
(x - 2)(x - 3) = 0

Answer 1

If the 2 zeros are x₁ and x₂, you multiply (x - x₁)(x - x₂).

 

x₁ = 2

x₂ = -3

 

(x - x₁)(x - x₂) = (x - 2)(x + 3) = 0