Find the value of k

Question

Find this value of k such that the graph of y= 2(x-3)^2+k will pass through the point (-2,55).

Answer 1

You have the formula of the quadratic equation as y=2(x-3)²+k where it passes through the point (-2,55).

All you need to do is put in the value of x & y from the point (-2,55) and solve for k.

y=2(x-3)²+k

55=2(-2-3)²+k

55=2(-5)²+k

55=2(25)+k

55=50+k

k=55-50

k=5