Jill W.

asked • 10/01/14

2M/(M/20+M/25)

If Teddy rides his bike to school at 20 mph and rides home the same way at 25 mph, what is his average speed in miles per hour? 

2 Answers By Expert Tutors

By:

Jill W.

I don't understand how why you set up the equation in the 1st step. where does the 5/100 + 4/100 come from?
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10/01/14

Arthur D.

tutor
to add 1/20 and 1/25 you need a common denominator which is 100
1*5/20*5=5/100 and 4*1/4*25=4/100
4/100 + 5/100=(4+5)/100=9/100
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10/01/14

Greg C.

Intuition does now always rule :(  You cannot just take the arithmetic mean of 20 and 25, because they both did not take the same amount of time, only the same amount of distance, and so, therefore, Arthur's answer directly answers the question.
 
And you can prove it: If his home is 25 miles away, then it take 1 hour.  If he goes the 25 miles at 20mph then it takes him 1.25 hours.  So together, he's gone 50 miles in 2.25hours:
 
50
--- = 22.22
2.25
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10/01/14

Jill W.

ok, thank you to all! :-)
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10/01/14

Byron S.

This is essentially what Arthur's answer is, without the messy details. Average speed is total distance over total time. If you use the equation d = r*t for both legs of the trip, your total distance is 2d. Your time for each leg is d/r, so a total of d/20 + d/25.
 
Put these in a fraction 2d / (d/20 + d/25) and the d's cancel, reducing to the equation that Arthur started with and Greg used with a specific distance for clarity.
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10/01/14

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