Victoria V. answered • 09/11/18

Tutor

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Math Teacher: 20 Yrs Teaching/Tutoring Calculus, PreCalc, Alg 2, Trig

distance = rate * time

time is the same for both the plane and the car, so solve this for time:

time = distance/rate

time (plane) = distance (plane)/rate(plane)

time (car) = distance (car) / rate (car)

and the times are the same, so

plane dist/plane rate = car dist/car rate

Put numbers in now (r = rate of the car):

2030/(r+348) = 290/r

Solve this by cross multiplying

2030 r = 290 (r+348)

Distribute the 290 into the (r+ 348)

2030 r = 290 r + 100920

Subtract 290 r from both sides

1740 r = 100920

Divide both sides by 1740

r = 100920/1740 = 58 miles per hour

This is the rate of the CAR.

The rate of the plane is 348 mph faster than the car, so the plane is travelling at a rate of

58 + 348 = 406 miles per hour.