
Russ P. answered 09/29/14
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Rachel,
First notice that you have a repeating cycle of 20 days (primary teacher in first 12, then substitute in 8).
The number of cycles n = 252/20 = 12.6, so you have 12 complete cycles and a final 13th partial cycle of 12 days (=0.6 of 20) which happens to be taught by the primary teacher again. There is no need for a substitute in this 13th cycle.
Then let x= total # of days taught be the primary teacher
So x = 12*(n+1) = 12 * 13 = 156 days, and the subs teach 8*12 or 96 days
CHECK: 156 + 96 = 252 days!