3x - (8 - x) = 4[5 - (7 + 2x - 2)]

Question

whats the answer/ how to solve?

Answer 1

Hello, Josh

 

In order to do this problem follow the order of operations. So, let's start by evaluating the parenthesis inside the brackets: that becomes (5-2x). Now, inside the bracket we have [5-(5-2x)]= 5-5-2x.  In order words change what inside the parenthesis into its opposite since you are subtracting.  So, we get -2x. Rewriting it, we get:

 

3x-(8-x)= 4[-2x]         Use the distributive property

3x-(8-x)= -8x              Subtracting

3x-8+x = -8x               Combining like terms

4x-8    = -8x                Subtract 4x from both sides

-4x          -4x

    -8   =   -12x             Divide both sides by -12

     8/12 = x                  Reducing by dividing by 4

      2/3 = x.  

 

I hope this helps out.  Don't forget to check your answer, and thanks for posting.

 

D. Y. Taylor

dont forget to rate my answer :)@

Answer 2

3x - (8 - x) = 4[5 - (7 + 2x - 2)]

3x - 8 + x = 4(5 - 7 - 2x + 2)   

4x- 8 = 4( -2x)

4x- 8 = -8x

12x - 8 = 0

12x = 8

x= 8/12 = 2/3