Math help please

Question

You invested 26,000 in 2 accounts paying 6% and 8% annual interest. If the total interest earned for the year was $1980 how much was invested at each rate

Answer 1

X+Y = 26000

 

0.06X + 0.08Y = 1980

 

0.06X + 0.08(26000 - X) = 1980

 

0.06X + 2080 - 0.08X = 1980

 

2080 - 0.02X = 1980

 

-0.02X = 100

 

2X = 10000

 

X=5000

 

$5000 in the account at 6%

$21000 in the account at 8%