how can i factor 25r^2+80r+64

Question

i need help

Answer 1

Hello Valery

25r^2+80r+ 64 is an special case: ax^2+2ab+b^2.  Both the first and the last terms are perfect square.  In this case 25x^2 is a perfect square, 5x, and 64 is also a perfect square, 8.  

 

(5r+8) (5r+8) 

 

There is not much to explain.

 

D.Y. T.

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