Let H = the amt of high priced coffee and L = the amt of lower priced coffee
H + L = the total amt of coffee to be made = 30
6H = the cost of the higher priced coffee and 4L = the cost of the lower priced coffee
4.80*30 = the cost of the final amt of mixed coffee
6H + 4L = 4.8*30 => 3H + 2L =72
H + L = 30
3H + 2L = 72
Multiply the first equation by 2 and subtract it from the 2nd equation
2H + 2L = 60
3H + 2L = 72
H = 12 and then L = 30 - H = 18
You should take these two answers and check that they meet the stipulations in the question.