Given: f(x) = 5/(x-2) ; g(x) = 2x + 1
a) g(3) = 2(3) + 1 = 7
(f⚬g)(x) = 5/(g(3)-2) = 5/(7-2) = ___?
b) (f⚬g)(x) = 5/(g(x)-2) = 5/(2x+1-2) = 5/(2x-1)
(f⚬g)(3) = 5/(2(3)-1) = 5/(6-1) = ___?
Dark K.
asked 08/27/18
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