Philip P. answered • 09/25/14
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(-5a5b5)2(a3b3)5
= (-5)2(a5)2(b5)2(a3)5(b3)5
= (25)(a10)(b10)(a15)(b15)
= (25)*(a10*a15)*(b10*b15)
= 25*(a10+15)*(b10+15)
= 25a25b25
