Arthur D. answered 09/25/14
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distance=rate*time
16=r*(20/60)
16=r*(1/3)
48 mph=r (with the current)
16=r*(30/60)
16=r*(1/2)
32 mph=r (against the current)
let c=rate of the current
r+c=48 (with the current)
r-c=32 (against the current)
add the two equations
2r=80
r=40 mph
r+c=48
40+c=48
c=8 mph for the speed of the current, or...
r-c=32
40-c=32
-c=-8
c=8 mph again